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Let limx1(v(x))=\lim_{x \to 1}(v(x))=. find limx1+(v(x))\lim_{x \to 1^+}(v(x)) and limx1(v(x))\lim_{x \to 1^-}(v(x))

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Q. Let limx1(v(x))=\lim_{x \to 1}(v(x))=. find limx1+(v(x))\lim_{x \to 1^+}(v(x)) and limx1(v(x))\lim_{x \to 1^-}(v(x))
  1. Consider Behavior: To find limx1+(v(x))\lim_{x \to 1^+}(v(x)), we need to consider the behavior of v(x)v(x) as xx gets closer to 11 from values greater than 11.
  2. Limit Calculation: Since we're not given a specific function for v(x)v(x), we can't calculate the exact limit. However, we can say that if limx1(v(x))\lim_{x \to 1}(v(x)) exists and equals some value LL, then limx1+(v(x))\lim_{x \to 1+}(v(x)) should also equal LL, unless there's a discontinuity.
  3. Behavior Analysis: Similarly, to find limx1v(x)\lim_{x \to 1^-}v(x), we need to consider the behavior of v(x)v(x) as xx gets closer to 11 from values less than 11.
  4. Limit Existence: Again, without a specific function for v(x)v(x), we can't find the exact limit. But if limx1(v(x))\lim_{x \to 1}(v(x)) exists and equals LL, then limx1(v(x))\lim_{x \to 1^-}(v(x)) should also equal LL, unless there's a discontinuity.
  5. Discontinuity Consideration: Since we know that limx1(v(x))=.\lim_{x \to 1}(v(x)) = ., we can assume that both limx1+(v(x))\lim_{x \to 1^+}(v(x)) and limx1(v(x))\lim_{x \to 1^-}(v(x)) are also .., unless we're told otherwise about a discontinuity.

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