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Let 
g(x)=x^(-10).

g^(')(1)=

Let g(x)=x10 g(x)=x^{-10} .\newlineg(1)= g^{\prime}(1)=

Full solution

Q. Let g(x)=x10 g(x)=x^{-10} .\newlineg(1)= g^{\prime}(1)=
  1. Apply Power Rule: To find the derivative of g(x)=x10g(x) = x^{-10}, we need to use the power rule for differentiation, which states that the derivative of xnx^n with respect to xx is nxn1n \cdot x^{n-1}. So, we will apply this rule to g(x)g(x).
  2. Calculate Derivative: Applying the power rule to g(x)=x10g(x) = x^{-10}, we get g(x)=10x101=10x11g'(x) = -10 \cdot x^{-10-1} = -10 \cdot x^{-11}.
  3. Substitute x=1x=1: Now we need to evaluate the derivative at x=1x=1. So we substitute xx with 11 in the expression for g(x)g'(x) to get g(1)=10111g'(1) = -10\cdot1^{-11}.
  4. Evaluate g(1)g'(1): Since any non-zero number to the power of 11-11 is just its reciprocal, 1(11)1^{(-11)} is simply 11. Therefore, g(1)=10×1=10g'(1) = -10 \times 1 = -10.