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Let E={2,6}E = \{2, 6\} and F={1,3,4,5,7}F = \{1, 3, 4, 5, 7\}. What is E∩FE \cap F?\newlineChoices:\newline(A){1,2,3,4,5,6,7}\{1, 2, 3, 4, 5, 6, 7\}\newline(B) ∅\emptyset \newline(C){1,2,5,6}\{1, 2, 5, 6\}\newline(D){1,2,5,6,7}\{1, 2, 5, 6, 7\}

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Q. Let E={2,6}E = \{2, 6\} and F={1,3,4,5,7}F = \{1, 3, 4, 5, 7\}. What is E∩FE \cap F?\newlineChoices:\newline(A){1,2,3,4,5,6,7}\{1, 2, 3, 4, 5, 6, 7\}\newline(B) ∅\emptyset \newline(C){1,2,5,6}\{1, 2, 5, 6\}\newline(D){1,2,5,6,7}\{1, 2, 5, 6, 7\}
  1. Intersection Definition: The intersection of two sets, denoted by E∩FE \cap F, is the set of elements that are common to both EE and FF.
  2. List Set E: We list the elements of set E, which are {2,6}\{2, 6\}.
  3. List Set F: We list the elements of set F, which are {1,3,4,5,7}\{1, 3, 4, 5, 7\}.
  4. Compare Elements: We compare the elements of set EE with the elements of set FF to find common elements.
  5. No Common Elements: There are no elements that are common to both sets EE and FF, as 22 and 66 are not present in set FF.
  6. Intersection Result: Since there are no common elements, the intersection of EE and FF is the empty set, denoted by ∅\emptyset.

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