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Let’s check out your problem:
Let
a
a
a
,
b
b
b
,
c
c
c
be the three rational numbers where
a
=
2
3
a = \frac{2}{3}
a
=
3
2
,
b
=
4
5
b = \frac{4}{5}
b
=
5
4
and
c
=
−
5
6
c = -\frac{5}{6}
c
=
−
6
5
Verify: (i)
A
+
(
b
+
c
)
=
(
a
+
b
)
+
c
A + (b + c) = (a + b) + c
A
+
(
b
+
c
)
=
(
a
+
b
)
+
c
(Associative property of addition)
View step-by-step help
Home
Math Problems
Algebra 2
Descartes' Rule of Signs
Full solution
Q.
Let
a
a
a
,
b
b
b
,
c
c
c
be the three rational numbers where
a
=
2
3
a = \frac{2}{3}
a
=
3
2
,
b
=
4
5
b = \frac{4}{5}
b
=
5
4
and
c
=
−
5
6
c = -\frac{5}{6}
c
=
−
6
5
Verify: (i)
A
+
(
b
+
c
)
=
(
a
+
b
)
+
c
A + (b + c) = (a + b) + c
A
+
(
b
+
c
)
=
(
a
+
b
)
+
c
(Associative property of addition)
Calculate
b
+
c
b + c
b
+
c
:
Calculate
b
+
c
b + c
b
+
c
:
b
+
c
=
4
5
+
(
−
5
6
)
=
(
24
30
)
+
(
−
25
30
)
=
−
1
30
b + c = \frac{4}{5} + \left(-\frac{5}{6}\right) = \left(\frac{24}{30}\right) + \left(-\frac{25}{30}\right) = -\frac{1}{30}
b
+
c
=
5
4
+
(
−
6
5
)
=
(
30
24
)
+
(
−
30
25
)
=
−
30
1
.
Calculate
a
+
(
b
+
c
)
a + (b + c)
a
+
(
b
+
c
)
:
Calculate
a
+
(
b
+
c
)
a + (b + c)
a
+
(
b
+
c
)
:
a
+
(
b
+
c
)
=
2
3
+
(
−
1
30
)
=
(
20
30
)
+
(
−
1
30
)
=
19
30
a + (b + c) = \frac{2}{3} + \left(-\frac{1}{30}\right) = \left(\frac{20}{30}\right) + \left(-\frac{1}{30}\right) = \frac{19}{30}
a
+
(
b
+
c
)
=
3
2
+
(
−
30
1
)
=
(
30
20
)
+
(
−
30
1
)
=
30
19
.
Calculate
a
+
b
a + b
a
+
b
:
Calculate
a
+
b
a + b
a
+
b
:
a
+
b
=
2
3
+
4
5
=
(
10
15
)
+
(
12
15
)
=
22
15
a + b = \frac{2}{3} + \frac{4}{5} = \left(\frac{10}{15}\right) + \left(\frac{12}{15}\right) = \frac{22}{15}
a
+
b
=
3
2
+
5
4
=
(
15
10
)
+
(
15
12
)
=
15
22
.
Calculate
(
a
+
b
)
+
c
(a + b) + c
(
a
+
b
)
+
c
:
Calculate
(
a
+
b
)
+
c
(a + b) + c
(
a
+
b
)
+
c
:
(
a
+
b
)
+
c
=
22
15
+
(
−
5
6
)
=
(
44
30
)
+
(
−
25
30
)
=
19
30
(a + b) + c = \frac{22}{15} + \left(-\frac{5}{6}\right) = \left(\frac{44}{30}\right) + \left(-\frac{25}{30}\right) = \frac{19}{30}
(
a
+
b
)
+
c
=
15
22
+
(
−
6
5
)
=
(
30
44
)
+
(
−
30
25
)
=
30
19
.
More problems from Descartes' Rule of Signs
Question
Find the solutions of the quadratic equation
2
x
2
−
8
x
−
9
=
0
2 x^{2}-8 x-9=0
2
x
2
−
8
x
−
9
=
0
.
\newline
Choose
1
1
1
answer:
\newline
(A)
2
±
34
2
i
2 \pm \frac{\sqrt{34}}{2} i
2
±
2
34
i
\newline
(B)
−
2
±
34
2
i
-2 \pm \frac{\sqrt{34}}{2} i
−
2
±
2
34
i
\newline
(C)
2
±
34
2
2 \pm \frac{\sqrt{34}}{2}
2
±
2
34
\newline
(D)
1
±
34
4
1 \pm \frac{\sqrt{34}}{4}
1
±
4
34
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Posted 3 months ago
Question
x
3
+
7
x
2
−
36
x^{3}+7 x^{2}-36
x
3
+
7
x
2
−
36
\newline
The polynomial has zeros at
−
6
-6
−
6
and
2
2
2
. If the remaining zero is
z
z
z
, then what is the value of
−
z
-z
−
z
?
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Posted 3 months ago
Question
Solve for
x
x
x
.
\newline
Enter the solutions from least to greatest.
\newline
(
−
5
x
+
4
)
(
x
−
3
)
=
0
lesser
x
=
□
greater
x
=
□
\begin{array}{l} (-5 x+4)(x-3)=0 \\ \text { lesser } x=\square \\ \text { greater } x=\square \end{array}
(
−
5
x
+
4
)
(
x
−
3
)
=
0
lesser
x
=
□
greater
x
=
□
Get tutor help
Posted 3 months ago
Question
Solve for
x
x
x
.
\newline
Enter the solutions from least to greatest.
\newline
(
2
x
+
4
)
(
3
x
−
2
)
=
0
(2 x+4)(3 x-2)=0
(
2
x
+
4
)
(
3
x
−
2
)
=
0
\newline
lesser
x
=
x=
x
=
\newline
greater
x
=
x=
x
=
Get tutor help
Posted 3 months ago
Question
Solve for
x
x
x
.
\newline
Enter the solutions from least to greatest.
\newline
(
3
x
−
6
)
(
−
x
+
3
)
=
0
lesser
x
=
□
greater
x
=
□
\begin{array}{l} (3 x-6)(-x+3)=0 \\ \text { lesser } x=\square \\ \text { greater } x=\square \end{array}
(
3
x
−
6
)
(
−
x
+
3
)
=
0
lesser
x
=
□
greater
x
=
□
Get tutor help
Posted 3 months ago
Question
Solve for
x
x
x
.
\newline
Enter the solutions from least to greatest.
\newline
(
x
+
6
)
(
−
x
+
1
)
=
0
(x+6)(-x+1)=0
(
x
+
6
)
(
−
x
+
1
)
=
0
\newline
lesser
x
=
x=
x
=
\newline
greater
x
=
x=
x
=
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Posted 3 months ago
Question
Is the following function even, odd, or neither?
\newline
f
(
x
)
=
3
x
2
+
2
f(x)=\frac{3}{x^{2}+2}
f
(
x
)
=
x
2
+
2
3
\newline
Choose
1
1
1
answer:
\newline
(A) Even
\newline
(B) Odd
\newline
(C) Neither
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Posted 3 months ago
Question
Is the following function even, odd, or neither?
\newline
f
(
x
)
=
1
4
−
x
2
f(x)=\frac{1}{4-x^{2}}
f
(
x
)
=
4
−
x
2
1
\newline
Choose
1
1
1
answer:
\newline
(A) Even
\newline
(B) Odd
\newline
(C) Neither
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Posted 3 months ago
Question
Is the following function even, odd, or neither?
\newline
f
(
x
)
=
2
∣
x
∣
−
5
f(x)=2|x|-5
f
(
x
)
=
2∣
x
∣
−
5
\newline
Choose
1
1
1
answer:
\newline
(A) Even
\newline
(B) Odd
\newline
(C) Neither
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Posted 3 months ago
Question
Is the following function even, odd, or neither?
\newline
f
(
x
)
=
x
x
2
+
1
f(x)=\frac{x}{x^{2}+1}
f
(
x
)
=
x
2
+
1
x
\newline
Choose
1
1
1
answer:
\newline
(A) Even
\newline
(B) Odd
\newline
(C) Neither
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Posted 3 months ago