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What is the radius of this circle?

Leam with an example\newlineWhat is the radius of this circle?

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Q. Leam with an example\newlineWhat is the radius of this circle?
  1. Identify Equation: Step 11: Identify the equation of the circle and compare it to the standard form.\newlineThe given equation is x2+y2=36x^2 + y^2 = 36. The standard form of a circle's equation is (xh)2+(yk)2=r2(x - h)^2 + (y - k)^2 = r^2, where (h,k)(h, k) is the center and rr is the radius. Here, it looks like h=0h = 0 and k=0k = 0, so the equation simplifies to x2+y2=r2x^2 + y^2 = r^2.
  2. Solve for r2r^2: Step 22: Solve for r2r^2.\newlineFrom the equation x2+y2=36x^2 + y^2 = 36, we can see that r2=36r^2 = 36.
  3. Find Radius: Step 33: Find the radius rr by taking the square root of r2r^2. Taking the square root of both sides, we get r=36r = \sqrt{36}. This gives r=±6r = \pm 6.
  4. Determine Value: Step 44: Determine the appropriate value for the radius.\newlineSince a radius cannot be negative, we discard 6-6. Therefore, the radius of the circle is 66.

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