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le of 
a in these diagrams.
b
C

le of a a in these diagrams.\newlineb\newlineC

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Q. le of a a in these diagrams.\newlineb\newlineC
  1. Plug values into expression: We know a=2a = 2 and b=2ib = 2i, so plug these into the expression ab3ab^{3}.\newlineCalculation: 2×(2i)32 \times (2i)^{3}
  2. Calculate power of (2i)(2i): Calculate (2i)3(2i)^{3} by raising both the coefficient and the imaginary unit to the power of 33.\newlineCalculation: (23)(i3)(2^{3}) \cdot (i^{3})
  3. Simplify powers: Simplify the powers.\newlineCalculation: 8×i38 \times i^3
  4. Use i2=1i^2 = -1: Remember that i2=1i^2 = -1, so i3=i2i=1ii^3 = i^2 \cdot i = -1 \cdot i.\newlineCalculation: 8(1i)8 \cdot (-1 \cdot i)
  5. Multiply by -i: Multiply 88 by i-i.\newlineCalculation: 8×i=8i8 \times -i = -8i
  6. Multiply by 22: Now multiply the result by 22 from the first step.\newlineCalculation: 2×8i2 \times -8i
  7. Simplify multiplication: Simplify the multiplication.\newlineCalculation: 16i-16i

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