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Lateral Surface Area (LSA) of a Triangular Prism

LSA=(S_(1)+S_(2)+b)×1
here,

S_(1),S_(2) and
b= egdes of the base I = length of the prism

Lateral Surface Area (LSA) of a Triangular Prism $\newline$ $L S A=\left(S_{1}+S_{2}+b\right) \times 1$ $\newline$ here, $\newline$ $S_{1}, S_{2}$ and $b=$ egdes of the base I = length of the prism

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Circles: word problems

Full solution

Q. Lateral Surface Area (LSA) of a Triangular Prism

\newline

L S A=\left(S_{1}+S_{2}+b\right) \times 1

\newline

here,

\newline

S_{1}, S_{2}

and

b=

egdes of the base I = length of the prism

Calculate Perimeter: First, we need to add up the edges of the base to get the perimeter. $\newline$ Calculation: $5\,\text{cm} + 6\,\text{cm} + 7\,\text{cm} = 18\,\text{cm}$
Find LSA: Next, we multiply the perimeter by the length of the prism to find the LSA. $\newline$ Calculation: $18\,\text{cm} \times 10\,\text{cm} = 180\,\text{cm}^2$
Realize Mistake: Oops, I just realized I made a mistake. We don't need the perimeter for the LSA formula; we need the sum of the lateral edges. Since we don't have the individual lengths of the lateral edges, we can't solve this problem with the given information.

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