Khan Academy $\newline$ Get Al Tutoring $\newline$ NEW $\newline$ Donate $\newline$ $3(x+1)^{2}=108$ $\newline$ Solution steps: $\newline$ \begin{tabular}{|c|} $\newline$ \hline Add $1$ to both sides \\ $\newline$ \hline Divide both sides by $3$ \\ $\newline$ \hline Multiply both sides by $3$ \\ $\newline$ \hline Subtract $1$ from both sides \\ $\newline$ \hline Square both sides \\ $\newline$ \hline Take the square root of both \\ $\newline$ sides \\ $\newline$ \hline $\newline$ \end{tabular}

Full solution

Q. Khan Academy

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Get Al Tutoring

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NEW

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Donate

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3(x+1)^{2}=108

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Solution steps:

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\begin{tabular}{|c|}

\newline

\hline Add

1

to both sides \\

\newline

\hline Divide both sides by

3

\newline

\hline Multiply both sides by

3

\newline

\hline Subtract

1

from both sides \\

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\hline Square both sides \\

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\hline Take the square root of both \\

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sides \\

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\hline

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\end{tabular}

Divide by $3$ : Divide both sides by $3$ to isolate the squared term. $\newline$ Using the property of equality, if we divide both sides of the equation by the same number, the equality is maintained. $\newline$ Calculation: $\frac{3(x+1)^{2}}{3} = \frac{108}{3}$ $\newline$ Result: $(x+1)^{2} = 36$
Take Square Root: Take the square root of both sides to solve for $(x+1)$ . By taking the square root of both sides of the equation, we can find the value of $(x+1)$ . Calculation: $\sqrt{(x+1)^{2}} = \sqrt{36}$ Result: $x+1 = \pm 6$
Subtract $1$ : Subtract $1$ from both sides to solve for $x$ . We subtract $1$ from both sides to isolate $x$ . Calculation: $x+1 - 1 = \pm6 - 1$ Result: $x = \pm6 - 1$
Calculate Final Value: Calculate the final value of $x$ . We have two possible solutions since we took the square root. Calculation: $x = 6 - 1$ or $x = -6 - 1$ Result: $x = 5$ or $x = -7$