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[pi
Estela
degrees Celsius 
(^(@)C). If the speed increases by 
0.6(m)/(s) for every increase in temperature of 
1^(@)C, which inequality best represents the temperatures, 
T, in degrees Celsius, for which the speed of sound in air exceeds 
350(m)/(s) ?
Choose 1 answer:
(A) 
T < 30
(B) 
T <= 30
(C) 
T > 30
(D) 
T >= 30
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Khan Academy\newlineGet Al Tutoring\newlineNEW\newline\newlineDonate [π [\pi \newlineEstela\newlinedegrees Celsius (C) \left({ }^{\circ} \mathrm{C}\right) . If the speed increases by 0.6ms 0.6 \frac{\mathrm{m}}{\mathrm{s}} for every increase in temperature of 1C 1^{\circ} \mathrm{C} , which inequality best represents the temperatures, T T , in degrees Celsius, for which the speed of sound in air exceeds 350ms 350 \frac{\mathrm{m}}{\mathrm{s}} ?\newlineChoose 11 answer:\newline(A) T<30 T<30 \newline(B) T30 T \leq 30 \newline(C) T>30 T>30 \newline(D) T30 T \geq 30 \newlineShnuw ralrulator\newline44 of 1010

Full solution

Q. Khan Academy\newlineGet Al Tutoring\newlineNEW\newline\newlineDonate [π [\pi \newlineEstela\newlinedegrees Celsius (C) \left({ }^{\circ} \mathrm{C}\right) . If the speed increases by 0.6ms 0.6 \frac{\mathrm{m}}{\mathrm{s}} for every increase in temperature of 1C 1^{\circ} \mathrm{C} , which inequality best represents the temperatures, T T , in degrees Celsius, for which the speed of sound in air exceeds 350ms 350 \frac{\mathrm{m}}{\mathrm{s}} ?\newlineChoose 11 answer:\newline(A) T<30 T<30 \newline(B) T30 T \leq 30 \newline(C) T>30 T>30 \newline(D) T30 T \geq 30 \newlineShnuw ralrulator\newline44 of 1010
  1. Denote Initial Speed: Let's denote the initial speed of sound in air at 00 degrees Celsius as v0 v_0 . According to the given information, the speed of sound increases by 00.66(m/s) for every increase in temperature of 11 degree Celsius. Therefore, the speed of sound in air at temperature T degrees Celsius can be represented by the equation:\newlinev(T)=v0+0.6T v(T) = v_0 + 0.6T \newlineWe need to find the value of T for which v(T)>350 v(T) > 350 m/s.
  2. Given Information: We are not given the initial speed of sound v0 v_0 at 00 degrees Celsius, but we can assume it to be a constant value. Since we are looking for the temperature at which the speed exceeds 350350 m/s, we set up the inequality:\newlinev0+0.6T>350 v_0 + 0.6T > 350
  3. Setting Up Inequality: To solve for T, we need to isolate T on one side of the inequality. However, we do not have the value of v0 v_0 , so we cannot solve for T directly. We need additional information about the initial speed of sound at 00 degrees Celsius to proceed.
  4. Isolating Variable: Since we cannot determine the value of v0 v_0 from the given information, we cannot continue with the calculation. The problem seems to be missing the necessary information to solve for T. Without v0 v_0 , we cannot find the exact temperature at which the speed of sound exceeds 350350 m/s.