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Khan Academy
Donate [?
Naymet k
Quiz 4
Hannah's school hosted a book donation. There are 150 students at her school, and they donated a total of 
b books! Hannah donated 3 times as many as the average number of books each student donated.
How many books did Hannah donate?
Write your answer as an expression.
books
Report a problem

Khan Academy\newlineDonate [?\newlineNaymet k\newlineQuiz 44\newlineHannah's school hosted a book donation. There are 150150 students at her school, and they donated a total of b b books! Hannah donated 33 times as many as the average number of books each student donated.\newlineHow many books did Hannah donate?\newlineWrite your answer as an expression.\newlinebooks\newlineReport a problem

Full solution

Q. Khan Academy\newlineDonate [?\newlineNaymet k\newlineQuiz 44\newlineHannah's school hosted a book donation. There are 150150 students at her school, and they donated a total of b b books! Hannah donated 33 times as many as the average number of books each student donated.\newlineHow many books did Hannah donate?\newlineWrite your answer as an expression.\newlinebooks\newlineReport a problem
  1. Denote Total Number of Books: Let's denote the total number of books donated by all students as bb. The average number of books donated by each student is therefore bb divided by the total number of students, which is 150150. So, the average number of books per student is b150\frac{b}{150}.
  2. Calculate Hannah's Donation: Hannah donated 33 times the average number of books. To find out how many books Hannah donated, we multiply the average number of books per student by 33. This gives us 3×(b150)3 \times \left(\frac{b}{150}\right).
  3. Simplify Expression: Simplify the expression 3×(b150)3 \times \left(\frac{b}{150}\right) to get the final expression for the number of books Hannah donated. This simplification results in 3b150\frac{3b}{150}.
  4. Check for Common Factors: We can check if the expression (3b)/150(3b)/150 is simplified by looking for common factors in the numerator and the denominator. However, since there are no further common factors, the expression is already in its simplest form.

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