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Keisha is choosing a 2-letter password from the letters A, B, C, D, E, and F. The password cannot have the same letter repeated in it. How many such passwords are possible?

Keisha is choosing a $2$ -letter password from the letters A, B, C, D, E, and F. The password cannot have the same letter repeated in it. How many such passwords are possible?

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Understand fractions as division: word problems

Full solution

Q. Keisha is choosing a

2

-letter password from the letters A, B, C, D, E, and F. The password cannot have the same letter repeated in it. How many such passwords are possible?

First Letter Options: For the first letter of the password, Keisha has $6$ options (A, B, C, D, E, F).
Second Letter Options: After choosing the first letter, there are $5$ letters left for the second position since the same letter can't be used twice.
Total Possible Passwords: To find the total number of possible passwords, multiply the number of choices for the first letter by the number of choices for the second letter. $\newline$ So, $6$ (choices for first letter) $\times$ $5$ (choices for second letter) = $30$ possible passwords.

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