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Kayden is a stunt driver. One time, during a gig where she escaped from a building about to explode(!), she drove at a constant speed to get to the safe zone that was 160 meters away. After 3 seconds of driving, she was 85 meters away from the safe zone.
Let 
y represent the distance (in meters) from the safe zone after 
x seconds.
Complete the equation for the relationship between the distance and number of seconds.

y=◻

Kayden is a stunt driver. One time, during a gig where she escaped from a building about to explode(!), she drove at a constant speed to get to the safe zone that was 160160 meters away. After 33 seconds of driving, she was 8585 meters away from the safe zone.\newlineLet yy represent the distance (in meters) from the safe zone after xx seconds.\newlineComplete the equation for the relationship between the distance and number of seconds.\newliney=y=\square

Full solution

Q. Kayden is a stunt driver. One time, during a gig where she escaped from a building about to explode(!), she drove at a constant speed to get to the safe zone that was 160160 meters away. After 33 seconds of driving, she was 8585 meters away from the safe zone.\newlineLet yy represent the distance (in meters) from the safe zone after xx seconds.\newlineComplete the equation for the relationship between the distance and number of seconds.\newliney=y=\square
  1. Determine Initial Distance: Determine the initial distance from the safe zone and the distance covered in 33 seconds.\newlineKayden starts 160160 meters away from the safe zone and after 33 seconds, she is 8585 meters away. This means she covered 16085=75160 - 85 = 75 meters in 33 seconds.
  2. Calculate Speed: Calculate the speed at which Kayden is driving. Speed is the distance covered divided by the time taken. Kayden covered 7575 meters in 33 seconds, so her speed is 75 meters3 seconds=25 meters per second.\frac{75 \text{ meters}}{3 \text{ seconds}} = 25 \text{ meters per second}.
  3. Write Equation: Write the equation using the speed and the initial distance.\newlineSince Kayden is driving at a constant speed, the distance she is from the safe zone decreases linearly over time. The equation relating the distance from the safe zone, yy, after xx seconds is y=initial distance(speed×time)y = \text{initial distance} - (\text{speed} \times \text{time}). Using the values we have, the equation becomes y=16025xy = 160 - 25x.

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