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Joy is a contestant on the kids' game show, Spend or Switch! When she makes it up on stage, host Guy Granger takes out a stack of one hundred-dollar bills. He divides the bills evenly among all 88 contestants on stage. Each contestant receives 33 one hundred-dollar bills.\newlineWhich equation can you use to find the number of bills bb in Guy Granger's stack?\newlineChoices:\newline(A) b8=3\frac{b}{8} = 3\newline(B) b8=3b - 8 = 3\newline(C) b+8=3b + 8 = 3\newline(D) 8b=38b = 3\newlineSolve this equation for bb to find the number of bills in Guy Granger's stack.\newline____ bills\newline

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Q. Joy is a contestant on the kids' game show, Spend or Switch! When she makes it up on stage, host Guy Granger takes out a stack of one hundred-dollar bills. He divides the bills evenly among all 88 contestants on stage. Each contestant receives 33 one hundred-dollar bills.\newlineWhich equation can you use to find the number of bills bb in Guy Granger's stack?\newlineChoices:\newline(A) b8=3\frac{b}{8} = 3\newline(B) b8=3b - 8 = 3\newline(C) b+8=3b + 8 = 3\newline(D) 8b=38b = 3\newlineSolve this equation for bb to find the number of bills in Guy Granger's stack.\newline____ bills\newline
  1. Understand the problem: Understand the problem.\newlineJoy receives 33 one hundred-dollar bills, and this amount is evenly divided among all 88 contestants. We need to find the total number of bills bb that Guy Granger had originally.
  2. Set up the equation: Set up the equation.\newlineIf each contestant receives 33 bills and there are 88 contestants, the total number of bills is the number of contestants multiplied by the number of bills each contestant receives. The equation that represents this situation is b8=3\frac{b}{8} = 3, where bb is the total number of bills.
  3. Solve the equation for b: Solve the equation for b.\newlineTo find bb, we need to multiply both sides of the equation by 88 to isolate bb on one side.\newlineb8×8=3×8\frac{b}{8} \times 8 = 3 \times 8\newlineb=24b = 24
  4. Verify the solution: Verify the solution.\newlineIf we substitute bb with 2424 into the equation b8=3\frac{b}{8} = 3, we get:\newline248=3\frac{24}{8} = 3\newline3=33 = 3\newlineThis shows that our solution is correct.