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jolve the system of equ {:[4x-3y=-4],[4x+y=12]:}

jolve the system of equ\newline4x−3y=−44x+y=12 \begin{array}{c} 4 x-3 y=-4 \\ 4 x+y=12 \end{array}

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Full solution

Q. jolve the system of equ\newline4x−3y=−44x+y=12 \begin{array}{c} 4 x-3 y=-4 \\ 4 x+y=12 \end{array}
  1. Eliminate xx: Subtract the second equation from the first to eliminate xx.$4x−3y\$4x - 3y - 4x+y4x + y = −4-4 - 1212\)\-3y - y = -16\-4y = -16
  2. Solve for y: Divide both sides by −4-4 to solve for y.\newline−4y/−4=−16/−4-4y / -4 = -16 / -4\newliney=4y = 4
  3. Substitute y into equation: Substitute y=4y = 4 into the second equation to solve for xx.4x+y=124x + y = 124x+4=124x + 4 = 124x=12−44x = 12 - 44x=84x = 8
  4. Solve for x: Divide both sides by 44 to solve for x.\newline4x4=84\frac{4x}{4} = \frac{8}{4}\newlinex=2x = 2

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