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Jika 
log 2=0,3010 dan 
log 3=0,4771, nilai dari log 5 adalah . ...
A. 0,7781
D. 0,3224
B. 0,6990
E. 0,1436
C. 0,5229

22. Jika log2=0,3010 \log 2=0,3010 dan log3=0,4771 \log 3=0,4771 , nilai dari log 55 adalah . ...\newlineA. 00,77817781\newlineD. 00,32243224\newlineB. 00,69906990\newlineE. 00,14361436\newlineC. 00,52295229

Full solution

Q. 22. Jika log2=0,3010 \log 2=0,3010 dan log3=0,4771 \log 3=0,4771 , nilai dari log 55 adalah . ...\newlineA. 00,77817781\newlineD. 00,32243224\newlineB. 00,69906990\newlineE. 00,14361436\newlineC. 00,52295229
  1. Use Log Relationship: Use the relationship between the logs of prime numbers to find the value of log5\log 5. We know that log(ab)=loga+logb\log(ab) = \log a + \log b. Since 1010 is the product of 22 and 55, we can write log10\log 10 as log(2×5)\log(2 \times 5) which is equal to log2+log5\log 2 + \log 5. We also know that log10=1\log 10 = 1. So, log2+log5=1\log 2 + \log 5 = 1.
  2. Substitute Log 22: Substitute the given value of log 22 into the equation.\newlinelog2+log5=1\log 2 + \log 5 = 1\newline0.3010+log5=10.3010 + \log 5 = 1
  3. Solve for log5\log 5: Solve for log5\log 5.log5=10.3010\log 5 = 1 - 0.3010log5=0.6990\log 5 = 0.6990

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