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Jevonte is the oldest of four siblings whose ages are consecutive odd integers. If the sum of their ages is 128 , find Jevonte's age. Answer:

Jevonte is the oldest of four siblings whose ages are consecutive odd integers. If the sum of their ages is 128128 , find Jevonte's age.\newlineAnswer:

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Q. Jevonte is the oldest of four siblings whose ages are consecutive odd integers. If the sum of their ages is 128128 , find Jevonte's age.\newlineAnswer:
  1. Identify Youngest Sibling's Age: Let xx be the age of the youngest sibling.\newlineWhich represents the four consecutive odd integers?\newlineConsecutive odd integers increase by 22 each time.\newlineConsecutive odd integers: xx, x+2x+2, x+4x+4, x+6x+6
  2. Find Consecutive Odd Integers: Which equation represents the sum of 44 consecutive odd integers is 128128?\newlineAdd four consecutive odd integers and equate the sum to 128128.\newlineEquation: x+(x+2)+(x+4)+(x+6)=128x + (x+2) + (x+4) + (x+6) = 128
  3. Set Up Equation for Sum: Simplify the left side of x+(x+2)+(x+4)+(x+6)=128x + (x+2) + (x+4) + (x+6) = 128. \newlinex+(x+2)+(x+4)+(x+6)=128x + (x+2) + (x+4) + (x+6) = 128\newline(x+x+x+x)+(2+4+6)=128(x + x + x + x) + (2+4+6) = 128\newline4x+12=1284x + 12 = 128
  4. Simplify Equation: Isolate the variable term in 4x+12=1284x + 12 = 128.
    4x+12=1284x + 12 = 128
    4x+12−12=128−124x + 12 - 12 = 128 - 12
    4x=1164x = 116
  5. Isolate Variable Term: 4x=1164x = 116\newlineSolve for xx.\newline4x=1164x = 116\newline(4x)/4=116/4(4x)/4 = 116/4\newlinex=29x = 29
  6. Solve for x: We have:\newlinex=29x = 29\newlineWhat is Jevonte's age if he is the oldest sibling?\newlineJevonte's age as the oldest sibling: x+6x + 6\newline29+6=3529 + 6 = 35

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