Bytelearn - cat image with glassesAI tutor

Welcome to Bytelearn!

Let’s check out your problem:

Jen plans to sell homemade candles online. She spent $44\$44 on a melting pot, and she will spend $4\$4 on wax and $2\$2 on a jar for each candle she makes. She will sell her candles for $10\$10 each.\newlineWhich equation can you use to find cc, the number of candles Jen must sell for her sales to equal her expenses?\newlineChoices:\newline(A) 10c=44+4c+2c10c = 44 + 4c + 2c\newline(B) 44+4c=10c+2c44 + 4c = 10c + 2c\newlineHow many candles must Jen sell for her sales to equal her expenses?\newline____\_\_\_\_ candles\newline

Full solution

Q. Jen plans to sell homemade candles online. She spent $44\$44 on a melting pot, and she will spend $4\$4 on wax and $2\$2 on a jar for each candle she makes. She will sell her candles for $10\$10 each.\newlineWhich equation can you use to find cc, the number of candles Jen must sell for her sales to equal her expenses?\newlineChoices:\newline(A) 10c=44+4c+2c10c = 44 + 4c + 2c\newline(B) 44+4c=10c+2c44 + 4c = 10c + 2c\newlineHow many candles must Jen sell for her sales to equal her expenses?\newline____\_\_\_\_ candles\newline
  1. Set Up Equation: First, let's set up the equation to find the break-even point for Jen's candle business. Jen's expenses include a one-time cost of $44\$44 for the melting pot and variable costs of $4\$4 for wax and $2\$2 for a jar per candle. Her revenue per candle is $10\$10. So, the equation to represent this situation is:\newline10c=44+6c10c = 44 + 6c
  2. Isolate cc: Next, we need to isolate cc (the number of candles) on one side of the equation to solve for it. Subtract 6c6c from both sides:\newline10c6c=4410c - 6c = 44\newline4c=444c = 44
  3. Divide to Find c: Now, divide both sides by 44 to find the value of c:\newlinec=444c = \frac{44}{4}\newlinec=11c = 11

More problems from Solve linear equations with variables on both sides: word problems