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Jasina has a total of $0.80 in nickels and dimes, and she has 4 more nickels than dimes. Which of the following systems of equations can be used to find out how many n nickels and d dimes she has?
Choose 1 answer:
(A) d+n=4
0.1 d+0.05 n=0.8
(B) d+4=n
0.1 d+0.05 n=0.8
(C) d-n=4
0.1 d+0.05 n=0.8
(D) n-d=-4
0.1 d+0.05 n=0.8

Jasina has a total of $0.80 \$ 0.80 in nickels and dimes, and she has 44 more nickels than dimes. Which of the following systems of equations can be used to find out how many n n nickels and d d dimes she has?\newlineChoose 11 answer:\newline(A) d+n=40.1d+0.05n=0.8 d+n=4 \\ \quad 0.1 d+0.05 n=0.8\newline(B) d+4=n0.1d+0.05n=0.8 d+4=n \\ \quad 0.1 d+0.05 n=0.8\newline(C) dn=40.1d+0.05n=0.8 d-n=4 \\ \quad 0.1 d+0.05 n=0.8\newline(D) nd=40.1d+0.05n=0.8 n-d=-4 \\ \quad 0.1 d+0.05 n=0.8

Full solution

Q. Jasina has a total of $0.80 \$ 0.80 in nickels and dimes, and she has 44 more nickels than dimes. Which of the following systems of equations can be used to find out how many n n nickels and d d dimes she has?\newlineChoose 11 answer:\newline(A) d+n=40.1d+0.05n=0.8 d+n=4 \\ \quad 0.1 d+0.05 n=0.8\newline(B) d+4=n0.1d+0.05n=0.8 d+4=n \\ \quad 0.1 d+0.05 n=0.8\newline(C) dn=40.1d+0.05n=0.8 d-n=4 \\ \quad 0.1 d+0.05 n=0.8\newline(D) nd=40.1d+0.05n=0.8 n-d=-4 \\ \quad 0.1 d+0.05 n=0.8
  1. Translate Equation Relationship: Translate the information about the number of nickels and dimes into an equation.\newlineJasina has 44 more nickels than dimes. If we let nn represent the number of nickels and dd represent the number of dimes, then we can express this as n=d+4n = d + 4.
  2. Translate Total Value Equation: Translate the information about the total value of nickels and dimes into an equation.\newlineEach nickel is worth $0.05\$0.05 and each dime is worth $0.10\$0.10. The total value of the nickels and dimes is $0.80\$0.80. This can be expressed as 0.05n+0.10d=0.800.05n + 0.10d = 0.80.
  3. Identify Matching System of Equations: Identify the system of equations that matches the equations from Step 11 and Step 22.\newlineWe are looking for a system of equations that includes both the relationship between the number of nickels and dimes n=d+4n = d + 4 and the total value of the nickels and dimes 0.05n+0.10d=0.800.05n + 0.10d = 0.80.
  4. Compare Given Options: Compare the options given with the equations we have formed.\newlineOption (A) d+n=4d + n = 4 and 0.1d+0.05n=0.80.1d + 0.05n = 0.8 does not match our equations.\newlineOption (B) d+4=nd + 4 = n and 0.1d+0.05n=0.80.1d + 0.05n = 0.8 matches our equations if we rearrange the first equation to n=d+4n = d + 4.\newlineOption (C) dn=4d - n = 4 and 0.1d+0.05n=0.80.1d + 0.05n = 0.8 does not match our equations.\newlineOption (D) nd=4n - d = -4 and 0.1d+0.05n=0.80.1d + 0.05n = 0.8 does not match our equations.
  5. Select Correct Equations: Select the correct system of equations.\newlineThe correct system of equations is given by Option (B) d+4=nd + 4 = n and 0.1d+0.05n=0.80.1d + 0.05n = 0.8, which matches the equations we derived from the problem statement.