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It is believed that 71%71\% of tickets purchased for an upcoming music festival are actually legitimate tickets. The rest are fake tickets sold by scam artists. Assume everyone who bought a ticket shows up at the concert.\newlineIf security guards at the festival randomly select 44 tickets to examine in more detail, what is the probability that exactly 11 of those tickets is legitimate?\newlineWrite your answer as a decimal rounded to the nearest thousandth.\newline____\newline

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Q. It is believed that 71%71\% of tickets purchased for an upcoming music festival are actually legitimate tickets. The rest are fake tickets sold by scam artists. Assume everyone who bought a ticket shows up at the concert.\newlineIf security guards at the festival randomly select 44 tickets to examine in more detail, what is the probability that exactly 11 of those tickets is legitimate?\newlineWrite your answer as a decimal rounded to the nearest thousandth.\newline____\newline
  1. Use Binomial Probability Formula: Use the binomial probability formula: P(X=k)=C(n,k)(p)k(1p)(nk)P(X = k) = C(n, k) \cdot (p)^k \cdot (1-p)^{(n-k)}. Here, n=4n = 4, k=1k = 1, and p=0.71p = 0.71.
  2. Calculate C(4,1)C(4, 1): Calculate C(4,1)C(4, 1) which is 4!1!×(41)!\frac{4!}{1! \times (4 - 1)!}. That's 41\frac{4}{1} which is 44.
  3. Calculate (0.71)1(0.71)^1: Now calculate (0.71)1(0.71)^1 which is just 0.710.71.
  4. Calculate (10.71)(41)(1 - 0.71)^{(4 - 1)}: Next, calculate (10.71)(41)(1 - 0.71)^{(4 - 1)}. That's (0.29)3(0.29)^3.
  5. Calculate (0.29)3(0.29)^3: (0.29)3(0.29)^3 equals 0.29×0.29×0.290.29 \times 0.29 \times 0.29, which is 0.0243890.024389.
  6. Multiply All Values Together: Now multiply all the values together: 4×0.71×0.0243894 \times 0.71 \times 0.024389.
  7. Multiply All Values Together: Now multiply all the values together: 4×0.71×0.0243894 \times 0.71 \times 0.024389.The multiplication gives us 4×0.71×0.0243894 \times 0.71 \times 0.024389 equals 0.06920.0692 when rounded to the nearest thousandth.

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