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Isaiah has a collection of vintage action figures that is worth 
$210. If the collection appreciates at a rate of 
12.1% per year, which equation represents the value of the collection after 3 years?

V=210(1-0.121)^(3)

V=210(1+0.121)

V=210(0.121)^(3)

V=210(1+0.121)(1+0.121)(1+0.121)

Isaiah has a collection of vintage action figures that is worth $210 \$ 210 . If the collection appreciates at a rate of 12.1% 12.1 \% per year, which equation represents the value of the collection after 33 years?\newlineV=210(10.121)3 V=210(1-0.121)^{3} \newlineV=210(1+0.121) V=210(1+0.121) \newlineV=210(0.121)3 V=210(0.121)^{3} \newlineV=210(1+0.121)(1+0.121)(1+0.121) V=210(1+0.121)(1+0.121)(1+0.121)

Full solution

Q. Isaiah has a collection of vintage action figures that is worth $210 \$ 210 . If the collection appreciates at a rate of 12.1% 12.1 \% per year, which equation represents the value of the collection after 33 years?\newlineV=210(10.121)3 V=210(1-0.121)^{3} \newlineV=210(1+0.121) V=210(1+0.121) \newlineV=210(0.121)3 V=210(0.121)^{3} \newlineV=210(1+0.121)(1+0.121)(1+0.121) V=210(1+0.121)(1+0.121)(1+0.121)
  1. Identify Values: We need to find the equation that correctly calculates the value of the collection after 33 years with an appreciation rate of 12.1%12.1\% per year. The general formula for compound interest (which is similar to appreciation) is V=P(1+r)tV = P(1 + r)^t, where VV is the future value, PP is the initial principal balance, rr is the rate of interest per period, and tt is the number of periods.
  2. Substitute Values: Let's identify the values from the problem:\newlineInitial value PP = $210\$210\newlineAnnual appreciation rate rr = 12.1%12.1\% = 0.1210.121 (as a decimal)\newlineNumber of years tt = 33\newlineNow we can substitute these values into the formula.
  3. Check Given Options: Substitute the values into the formula: V=P(1+r)tV = P(1 + r)^tV=210(1+0.121)3V = 210(1 + 0.121)^3This equation represents the value of the collection after 33 years, taking into account the annual appreciation.
  4. Final Equation: Now let's check the given options to see which one matches our equation:\newlineV=210(10.121)3V=210(1-0.121)^{3} - This is incorrect because it subtracts the rate instead of adding it.\newlineV=210(1+0.121)V=210(1+0.121) - This is incorrect because it does not account for compounding over 33 years.\newlineV=210(0.121)3V=210(0.121)^{3} - This is incorrect because it only raises the rate to the power of 33, not the entire term (1+rate)(1 + \text{rate}).\newlineV=210(1+0.121)(1+0.121)(1+0.121)V=210(1+0.121)(1+0.121)(1+0.121) - This is the expanded form of our correct equation and is equivalent to V=210(1+0.121)3V = 210(1 + 0.121)^3.

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