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Is u=17u = 17 a solution to this equation?\newline0=17u0 = \frac{17}{u}\newlineChoices:\newline(A)yes\newline(B)no

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Full solution

Q. Is u=17u = 17 a solution to this equation?\newline0=17u0 = \frac{17}{u}\newlineChoices:\newline(A)yes\newline(B)no
  1. Identify Equation After Substitution: We have the equation 0=17u0 = \frac{17}{u}. Identify the equation after substituting u=17u = 17. Substitute 1717 for uu in 0=17u0 = \frac{17}{u}. Equation: 0=17170 = \frac{17}{17}
  2. Simplify 17/1717/17: Simplify 17/1717/17. \newline17/17=117/17 = 1
  3. Check Solution for u=17u=17: We found that 1717\frac{17}{17} equals 11. Is u=17u = 17 a solution to the equation 0=17u0 = \frac{17}{u}? For u=17u=17, the equation becomes 0=10 = 1, which is not true. So, u=17u = 17 is not a solution to the equation 0=17u0 = \frac{17}{u}.

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