Bytelearn - cat image with glassesAI tutor

Welcome to Bytelearn!

Let’s check out your problem:

Is the function j(x)=11x218j(x) = 11x^2 - 18 even, odd, or neither?\newlineChoices:\newline(A)even\newline(B)odd\newline(C)neither

Full solution

Q. Is the function j(x)=11x218j(x) = 11x^2 - 18 even, odd, or neither?\newlineChoices:\newline(A)even\newline(B)odd\newline(C)neither
  1. Check Even Function: Check if j(x)j(x) is even by evaluating j(x)j(-x) and comparing it to j(x)j(x).\newlinej(x)=11(x)218j(-x) = 11(-x)^2 - 18
  2. Simplify j(x)j(-x): Simplify j(x)j(-x).j(x)=11x218j(-x) = 11x^2 - 18
  3. Compare Functions: Compare j(x)j(-x) with j(x)j(x).\newlineSince j(x)=j(x)j(-x) = j(x), the function j(x)j(x) is even.

More problems from Even and odd functions