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Is $(8,\,3)$ a solution to this system of inequalities? $\newline$ $x \geq 8$ $\newline$ $y < x + 1$ $\newline$ Choices: $\newline$ (A)yes $\newline$ (B)no

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Is (x, y) a solution to the system of linear inequalities?

Full solution

Q. Is

(8,\,3)

a solution to this system of inequalities?

\newline

x \geq 8

\newline

y < x + 1

\newline

Choices:

\newline

(A)yes

\newline

(B)no

Check $x \geq 8$ : Check if $(8, 3)$ satisfies the inequality $x \geq 8$ . $\newline$ Substitute $8$ for $x$ . $\newline$ $8 \geq 8$ $\newline$ This is true.
Check $y < x + 1$ : Check if $(8, 3)$ satisfies the inequality $y < x + 1$ . $\newline$ Substitute $8$ for $x$ and $3$ for $y$ . $\newline$ $3 < 8 + 1$ $\newline$ $3 < 9$ $\newline$ This is also true.
Solution Verification: Since $(8, 3)$ satisfies both inequalities, it is a solution to the system.

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