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Is (8, 10)(8,\,10) a solution to this system of inequalities?\newliney<10x+1y < 10x + 1\newliney<x+10y < x + 10\newlineChoices:\newline(A)yes\newline(B)no

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Q. Is (8, 10)(8,\,10) a solution to this system of inequalities?\newliney<10x+1y < 10x + 1\newliney<x+10y < x + 10\newlineChoices:\newline(A)yes\newline(B)no
  1. Check First Inequality: Check if (8,10)(8, 10) satisfies the first inequality y<10x+1y < 10x + 1. Substitute x=8x = 8 and y=10y = 10. 10<10×8+110 < 10 \times 8 + 1 10<80+110 < 80 + 1 10<8110 < 81 The point (8,10)(8, 10) satisfies the first inequality.
  2. Check Second Inequality: Check if (8,10)(8, 10) satisfies the second inequality y<x+10y < x + 10.\newlineSubstitute x=8x = 8 and y=10y = 10.\newline10<8+1010 < 8 + 10\newline10<1810 < 18\newlineThe point (8,10)(8, 10) satisfies the second inequality.
  3. Solution Verification: Since (8,10)(8, 10) satisfies both inequalities, it is a solution to the system.

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