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Is (7, 10)(7,\ 10) a solution to this system of inequalities?\newliney<x+6y < x + 6\newliney<3x+3y < 3x + 3\newlineChoices:\newline(A)yes\newline(B)no

Full solution

Q. Is (7, 10)(7,\ 10) a solution to this system of inequalities?\newliney<x+6y < x + 6\newliney<3x+3y < 3x + 3\newlineChoices:\newline(A)yes\newline(B)no
  1. Check Point (7,10)(7, 10): Check if the point (7,10)(7, 10) satisfies the inequality y<x+6y < x + 6.\newlineSubstitute x=7x = 7 and y=10y = 10 into the inequality.\newline10<7+610 < 7 + 6\newline10<1310 < 13\newlineThe point (7,10)(7, 10) satisfies the first inequality.
  2. Substitute Values: Check if the point (7,10)(7, 10) satisfies the inequality y<3x+3y < 3x + 3.\newlineSubstitute x=7x = 7 and y=10y = 10 into the inequality.\newline10<3×7+310 < 3 \times 7 + 3\newline10<21+310 < 21 + 3\newline10<2410 < 24\newlineThe point (7,10)(7, 10) satisfies the second inequality.

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