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Is (5, 2)(5,\,2) a solution to the inequality 3x+y<193x + y < 19?\newlineChoices:\newline(A)yes\newline(B)no

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Q. Is (5, 2)(5,\,2) a solution to the inequality 3x+y<193x + y < 19?\newlineChoices:\newline(A)yes\newline(B)no
  1. Substitute values into inequality: Substitute the values (5,2)(5, 2) into the inequality 3x+y<193x + y < 19. The substituted inequality is 3(5)+(2)<193(5) + (2) < 19.
  2. Calculate left side: Calculate the left side of the inequality 3(5)+(2)3(5) + (2). Simplify it to get 3×5+23\times 5 + 2 which equals 15+215 + 2.
  3. Add numbers: Add the numbers to get the sum, which is 15+2=1715 + 2 = 17.
  4. Check if inequality is true: Now we have the inequality 17<1917 < 19. Determine if the point (5,2)(5, 2) makes the inequality 3x+y<193x + y < 19 true. Since 1717 is less than 1919, the statement is true.

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