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Is (3,10)(3,10) a solution to this system of equations?\newliney=9x+10y = 9x + 10\newliney=3x+1y = 3x + 1\newlineChoices:\newline(A)yes\newline(B)no

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Q. Is (3,10)(3,10) a solution to this system of equations?\newliney=9x+10y = 9x + 10\newliney=3x+1y = 3x + 1\newlineChoices:\newline(A)yes\newline(B)no
  1. Substitute and Check: First, we will substitute the point (3,10)(3,10) into the first equation and check if it holds true. The first equation is y=9x+10y = 9x + 10. If we substitute x=3x=3 and y=10y=10, we get 10=9×3+1010 = 9 \times 3 + 10.
  2. Calculation Result: After performing the calculation, we find that 10=27+1010 = 27 + 10, which is not true. Therefore, the point (3,10)(3,10) does not satisfy the first equation. Since the point does not satisfy the first equation, there is no need to check the second equation.
  3. Point Not a Solution: Since the point (3,10)(3,10) does not satisfy both equations, it is not a solution to the system of equations.

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