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Is (3,1)(3,1) a solution to this system of equations?\newline2x+y=72x + y = 7\newline2x+4y=102x + 4y = 10\newlineChoices:\newline(A) yes\newline(B) no

Full solution

Q. Is (3,1)(3,1) a solution to this system of equations?\newline2x+y=72x + y = 7\newline2x+4y=102x + 4y = 10\newlineChoices:\newline(A) yes\newline(B) no
  1. Check First Equation: We need to check if the point (3,1)(3, 1) satisfies the first equation:\newline2x+y=72x + y = 7\newlineSubstitute x=3x = 3 and y=1y = 1 into the equation:\newline2(3)+1=72(3) + 1 = 7\newline6+1=76 + 1 = 7\newline7=77 = 7\newlineThe point (3,1)(3, 1) satisfies the first equation.
  2. Check Second Equation: Now, we need to check if the point (3,1)(3, 1) satisfies the second equation:\newline2x+4y=102x + 4y = 10\newlineSubstitute x=3x = 3 and y=1y = 1 into the equation:\newline2(3)+4(1)=102(3) + 4(1) = 10\newline6+4=106 + 4 = 10\newline10=1010 = 10\newlineThe point (3,1)(3, 1) satisfies the second equation.
  3. Confirm Solution: Since the point (3,1)(3, 1) satisfies both equations in the system, we can conclude that (3,1)(3, 1) is indeed a solution to the system of equations.

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