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Is (2,7)(2,7) a solution to this system of equations?\newliney=3x+1y = 3x + 1\newliney=2x+5y = 2x + 5\newlineChoices:\newline(A)yes\newline(B)no

Full solution

Q. Is (2,7)(2,7) a solution to this system of equations?\newliney=3x+1y = 3x + 1\newliney=2x+5y = 2x + 5\newlineChoices:\newline(A)yes\newline(B)no
  1. Substitute and Check First Equation: First, we will substitute the point (2,7)(2,7) into the first equation and check if it holds true. The first equation is y=3x+1y = 3x + 1. If we substitute x=2x=2 and y=7y=7, we get 7=3×2+17 = 3 \times 2 + 1.
  2. Check First Equation Result: After performing the calculation, we find that 7=6+17 = 6 + 1, which simplifies to 7=77 = 7. This is true. Therefore, the point (2,7)(2,7) satisfies the first equation.
  3. Substitute and Check Second Equation: Next, we will substitute the point (2,7)(2,7) into the second equation and check if it holds true. The second equation is y=2x+5y = 2x + 5. If we substitute x=2x=2 and y=7y=7, we get 7=2×2+57 = 2\times 2 + 5.
  4. Check Second Equation Result: After performing the calculation, we find that 7=4+57 = 4 + 5, which simplifies to 7=97 = 9. This is not true. Therefore, the point (2,7)(2,7) does not satisfy the second equation.
  5. Final Solution Determination: Since the point (2,7)(2,7) does not satisfy both equations, it is not a solution to the system of equations.

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