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Is (−2,−3)(-2, -3) a solution to the equation y=x2+−1y = x^2 + -1?\newlineChoices:\newline(A)yes\newline(B)no

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Q. Is (−2,−3)(-2, -3) a solution to the equation y=x2+−1y = x^2 + -1?\newlineChoices:\newline(A)yes\newline(B)no
  1. Substitute and Calculate: To check if the point (−2,−3)(-2, -3) is a solution, substitute x=−2x = -2 and y=−3y = -3 into the equation y=x2−1y = x^2 - 1.\newlineCalculation: y=(−2)2−1=4−1=3y = (-2)^2 - 1 = 4 - 1 = 3.
  2. Compare Values: Compare the calculated yy-value with the yy-coordinate of the point.\newlineCalculated y=3y = 3, Point's yy-coordinate =−3= -3.\newlineSince 3≠−33 \neq -3, the point (−2,−3)(-2, -3) is not a solution to the equation.

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