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Is $(10,\,1)$ a solution to the inequality $y < 10x + 2$ ? $\newline$ Choices: $\newline$ (A)yes $\newline$ (B)no

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Does (x, y) satisfy the inequality?

Full solution

Q. Is

(10,\,1)

a solution to the inequality

y < 10x + 2

?

\newline

Choices:

\newline

(A)yes

\newline

(B)no

Substitute values into inequality: Substitute the values $10, 1$ into the inequality $y < 10x + 2$ . The substituted inequality is $1 < 10(10) + 2$ .
Calculate right side: Calculate the right side of the inequality $10(10) + 2$ . Simplify it to get $100 + 2$ , which equals $102$ .
Evaluate the inequality: The inequality $1 < 10(10) + 2$ becomes $1 < 102$ . Now, determine if the point $(10, 1)$ makes the inequality $y < 10x + 2$ true. $1 < 102$ is a true statement.
Check satisfaction of point: Since $1$ is less than $102$ , the point $(10, 1)$ does satisfy the inequality $y < 10x + 2$ .

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