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Is $(1,\,7)$ a solution to this system of inequalities? $\newline$ $y \leq 7$ $\newline$ $11x + y < 20$ $\newline$ Choices: $\newline$ (A)yes $\newline$ (B)no

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Is (x, y) a solution to the system of linear inequalities?

Full solution

Q. Is

(1,\,7)

a solution to this system of inequalities?

\newline

y \leq 7

\newline

11x + y < 20

\newline

Choices:

\newline

(A)yes

\newline

(B)no

Check Inequality $y \leq 7$ : First, let's check if the point $(1, 7)$ satisfies the inequality $y \leq 7$ . Substitute $1$ for $x$ and $7$ for $y$ in $y \leq 7$ . $7 \leq 7$ Since $7$ is equal to $7$ , the inequality holds true.
Check Inequality $11x + y < 20$ : Next, let's check if the point $(1, 7)$ satisfies the inequality $11x + y < 20$ . Substitute $1$ for $x$ and $7$ for $y$ in $11x + y < 20$ . $11(1) + 7 < 20$ $11 + 7 < 20$ $(1, 7)$ $0$ Since $(1, 7)$ $1$ is less than $(1, 7)$ $2$ , the inequality holds true.
Solution Verification: Since the point $(1, 7)$ satisfies both inequalities $y \leq 7$ and $11x + y < 20$ , it is a solution to the system of inequalities.

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