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Is (1,7)(1,7) a solution to this system of equations?\newliney=5x+5y = 5x + 5\newliney=6x+1y = 6x + 1\newlineChoices:\newline(A)yes\newline(B)no

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Q. Is (1,7)(1,7) a solution to this system of equations?\newliney=5x+5y = 5x + 5\newliney=6x+1y = 6x + 1\newlineChoices:\newline(A)yes\newline(B)no
  1. Substitute and Check: First, we will substitute the point (1,7)(1,7) into the first equation and check if it holds true. The first equation is y=5x+5y = 5x + 5. If we substitute x=1x=1 and y=7y=7, we get 7=5×1+57 = 5 \times 1 + 5.
  2. Calculation Result: After performing the calculation, we find that 7=5+57 = 5 + 5, which is not true because 5+55 + 5 equals 1010, not 77. Therefore, the point (1,7)(1,7) does not satisfy the first equation.
  3. Conclusion: Since the point (1,7)(1,7) does not satisfy the first equation, there is no need to check the second equation. We can conclude that (1,7)(1,7) is not a solution to the system of equations.

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