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Is (1,−7)(1, -7) a solution to the equation y=7x2+−7x−9y = 7x^2 + -7x - 9?\newlineChoices:\newline(A) yes\newline(B) no

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Q. Is (1,−7)(1, -7) a solution to the equation y=7x2+−7x−9y = 7x^2 + -7x - 9?\newlineChoices:\newline(A) yes\newline(B) no
  1. Substitute x=1x = 1: To determine if (1,−7)(1, -7) is a solution, substitute x=1x = 1 and y=−7y = -7 into the equation and check if the equation holds true.\newlineCalculation: Substitute x=1x = 1 into y=7x2−7x−9y = 7x^2 - 7x - 9.\newliney=7(1)2−7(1)−9=7−7−9=−9y = 7(1)^2 - 7(1) - 9 = 7 - 7 - 9 = -9.
  2. Calculate yy: Now, compare the calculated yy-value with the yy-value from the point (1,−7)(1, -7). The calculated yy-value is −9-9, but the given yy-value is −7-7. Since −9≠−7-9 \neq -7, the point (1,−7)(1, -7) does not satisfy the equation.

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