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Is $(1,\ 4)$ a solution to the inequality $19x + y \leq 11$ ? $\newline$ Choices: $\newline$ (A)yes $\newline$ (B)no

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Does (x, y) satisfy the inequality?

Full solution

Q. Is

(1,\ 4)

a solution to the inequality

19x + y \leq 11

?

\newline

Choices:

\newline

(A)yes

\newline

(B)no

Substitute values into inequality: Substitute the values $(1, 4)$ into the inequality $19x + y \leq 11$ . The substituted inequality is $19(1) + 4 \leq 11$ .
Simplify left side: Simplify the left side of the inequality $19(1) + 4$ to get $19 + 4$ , which equals $23$ .
Evaluate inequality: The inequality $19(1) + 4 \leq 11$ becomes $23 \leq 11$ . Now, determine if the point $(1, 4)$ makes the inequality $19x + y \leq 11$ true. Since $23$ is not less than or equal to $11$ , the statement is false. Therefore, the point $(1, 4)$ does not make the inequality $19x + y \leq 11$ true.

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