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Is (1, 2)(1,\ 2) a solution to this system of inequalities?\newliney<10x+1y < 10x + 1\newliney<x+4y < x + 4\newlineChoices:\newline(A)yes\newline(B)no

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Q. Is (1, 2)(1,\ 2) a solution to this system of inequalities?\newliney<10x+1y < 10x + 1\newliney<x+4y < x + 4\newlineChoices:\newline(A)yes\newline(B)no
  1. Check First Inequality: Check if (1,2)(1, 2) satisfies the first inequality y<10x+1y < 10x + 1. Substitute x=1x = 1 and y=2y = 2 into the inequality. 2<10×1+12 < 10 \times 1 + 1 2<10+12 < 10 + 1 2<112 < 11 The point (1,2)(1, 2) satisfies the first inequality.
  2. Check Second Inequality: Check if (1,2)(1, 2) satisfies the second inequality y<x+4y < x + 4.\newlineSubstitute x=1x = 1 and y=2y = 2 into the inequality.\newline2<1+42 < 1 + 4\newline2<52 < 5\newlineThe point (1,2)(1, 2) satisfies the second inequality.
  3. Solution to System: Since (1,2)(1, 2) satisfies both inequalities, it is a solution to the system of inequalities.

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