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Is (1, 1)(1,\,1) a solution to the inequality 7x+10y<187x + 10y < 18 ?\newlineChoices:\newline(A)yes\newline(B)no

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Does (x, y) satisfy the inequality?right chevron icon

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Q. Is (1, 1)(1,\,1) a solution to the inequality 7x+10y<187x + 10y < 18 ?\newlineChoices:\newline(A)yes\newline(B)no
  1. Substitute values into inequality: Substitute the values (1,1)(1, 1) into the inequality 7x+10y<187x + 10y < 18. The substituted inequality is 7(1)+10(1)<187(1) + 10(1) < 18.
  2. Simplify left side: Simplify the left side of the inequality 7(1)+10(1)7(1) + 10(1) to get 7+107 + 10.
  3. Add numbers together: Add the numbers together to get 1717. So, 7+107 + 10 equals 1717.
  4. Check if statement is true: The inequality now reads 17<1817 < 18. Determine if this is a true statement.
  5. Verify point satisfies inequality: Since 1717 is less than 1818, the statement 17<1817 < 18 is true. Therefore, the point (1,1)(1, 1) does make the inequality 7x+10y<187x + 10y < 18 true.

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