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Is $(1,\ 1)$ a solution to the inequality $6x + 13y < 20$ ? $\newline$ Choices: $\newline$ (A)yes $\newline$ (B)no

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Does (x, y) satisfy the inequality?

Full solution

Q. Is

(1,\ 1)

a solution to the inequality

6x + 13y < 20

?

\newline

Choices:

\newline

(A)yes

\newline

(B)no

Substitute Values: Substitute the values $(1, 1)$ into the inequality $6x + 13y < 20$ . The substituted inequality is $6(1) + 13(1) < 20$ .
Simplify Left Side: Simplify the left side of the inequality $6(1) + 13(1)$ . This simplifies to $6 + 13$ .
Add Numbers: Add the numbers together to get $6 + 13 = 19$ .
Check Truth: The inequality now reads $19 < 20$ . Determine if this statement is true.
Verify Point: Since $19$ is less than $20$ , the statement $19 < 20$ is true. Therefore, the point $(1, 1)$ does make the inequality $6x + 13y < 20$ true.

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