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Integrate π4-\frac{\pi}{4} to +π4+\frac{\pi}{4} log(cosx+sinx)\log(\cos x + \sin x)

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Q. Integrate π4-\frac{\pi}{4} to +π4+\frac{\pi}{4} log(cosx+sinx)\log(\cos x + \sin x)
  1. Identify Function: Step 11: Identify the function to integrate.\newlineWe need to integrate log(cos(x)+sin(x))\log(\cos(x) + \sin(x)) from π4-\frac{\pi}{4} to π4\frac{\pi}{4}.
  2. Check Symmetry: Step 22: Check for symmetry.\newlineThe function log(cos(x)+sin(x))\log(\cos(x) + \sin(x)) is not obviously symmetric or antisymmetric, so we proceed with direct integration.
  3. Apply Techniques: Step 33: Apply integration techniques.\newlineWe start integrating log(cos(x)+sin(x))\log(\cos(x) + \sin(x)) from π4-\frac{\pi}{4} to π4\frac{\pi}{4}. This requires substitution or numerical methods since the integral of log\log functions combined with trigonometric functions isn't straightforward.
  4. Realize Mistake: Step 44: Realize a mistake in the function.\newlineThe correct function should be log(cos(x)+sin(x))\log(\cos(x) + \sin(x)), but it's written as log(cosx+since)\log(\cos x + \sin ce), which doesn't make sense mathematically. This is a typo and affects the calculation.

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