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e(ex)exdx\int e^{(e^{x})}e^{x}dx

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Q. e(ex)exdx\int e^{(e^{x})}e^{x}dx
  1. Recognize Pattern: Recognize the pattern in the integral.\newlineWe are given the integral of the function eexexe^{e^{x}} \cdot e^{x} with respect to xx. This resembles the pattern of an exponential function where the derivative of the exponent is present outside the exponential function.
  2. Make Substitution: Let u=exu = e^{x}.\newlineWe make a substitution to simplify the integral. Let u=exu = e^{x}. Then, we need to find the derivative of uu with respect to xx, which is dudx=ex\frac{du}{dx} = e^{x}.
  3. Rewrite in Terms of uu: Rewrite the integral in terms of uu. Since dudx=ex\frac{du}{dx} = e^{x}, we can write dx=duexdx = \frac{du}{e^{x}}. Now, we can substitute uu for exe^{x} and duex\frac{du}{e^{x}} for dxdx in the integral. The integral becomes eu(duex)\int e^{u} \cdot \left(\frac{du}{e^{x}}\right).
  4. Simplify Integral: Simplify the integral.\newlineNotice that exe^{x} is uu, so we can cancel exe^{x} in the numerator and the denominator. The integral simplifies to eudu\int e^{u} \, du.
  5. Integrate with uu: Integrate with respect to uu. The integral of eue^{u} with respect to uu is eu+Ce^{u} + C, where CC is the constant of integration.
  6. Substitute Back: Substitute back in terms of xx. We originally let u=exu = e^{x}, so we substitute back to get the integral in terms of xx. The result is eex+Ce^{e^{x}} + C.

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