Bytelearn - cat image with glassesAI tutor

Welcome to Bytelearn!

Let’s check out your problem:

int(x)/(sqrt(x^(2)+1))dx

xx2+1dx \int \frac{x}{\sqrt{x^{2}+1}} d x

Full solution

Q. xx2+1dx \int \frac{x}{\sqrt{x^{2}+1}} d x
  1. Simplify the integral: Step 11: Simplify the integral.\newlineWe start by recognizing a substitution that simplifies the integral. Let u=x2+1u = x^2 + 1, then du=2xdxdu = 2x dx. This means xdx=du2x dx = \frac{du}{2}.
  2. Substitute and adjust: Step 22: Substitute and adjust the integral.\newlineSubstitute uu and dudu into the integral:\newlinexx2+1dx=xu(du2)\int\frac{x}{\sqrt{x^2 + 1}} dx = \int\frac{x}{\sqrt{u}} \cdot \left(\frac{du}{2}\right)\newline=121udu= \frac{1}{2} \int\frac{1}{\sqrt{u}} \cdot du
  3. Integrate with new variable: Step 33: Integrate using the new variable.\newlineThe integral of 1u\frac{1}{\sqrt{u}} with respect to uu is 2u2\sqrt{u}. So,\newline121udu=122u+C\frac{1}{2} \int \frac{1}{\sqrt{u}} \, du = \frac{1}{2} \cdot 2 \cdot \sqrt{u} + C\newline=u+C= \sqrt{u} + C
  4. Substitute back to x: Step 44: Substitute back to x.\newlineSince u=x2+1u = x^2 + 1, u=x2+1\sqrt{u} = \sqrt{x^2 + 1}. Therefore,\newlineu+C=x2+1+C\sqrt{u} + C = \sqrt{x^2 + 1} + C