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int(x^(2)dx)/((x^(2)+16)^(2))

x2dx(x2+16)2 \int \frac{x^{2} d x}{\left(x^{2}+16\right)^{2}}

Full solution

Q. x2dx(x2+16)2 \int \frac{x^{2} d x}{\left(x^{2}+16\right)^{2}}
  1. Substitution and Simplification: Simplify the integral using a substitution.\newlineLet u=x2+16u = x^2 + 16, then du=2xdxdu = 2x dx.\newlineRewrite dxdx in terms of dudu: dx=du2xdx = \frac{du}{2x}.\newlineSubstitute into the integral:\newlinex2dx(x2+16)2=x2(du2x)u2\int \frac{x^2 dx}{(x^2 + 16)^2} = \int \frac{x^2 \cdot (\frac{du}{2x})}{u^2}\newline=12duu2= \frac{1}{2} \cdot \int \frac{du}{u^2}
  2. Further Simplification and Substitution: Simplify the integral further.\newlineThe integral becomes:\newline(12)(duu2)=(12)(1u)+C(\frac{1}{2}) \cdot \int(\frac{du}{u^2}) = (\frac{1}{2}) \cdot (-\frac{1}{u}) + C\newline=(12u)+C= -(\frac{1}{2u}) + C\newlineSubstitute back for u:\newline=(12(x2+16))+C= -(\frac{1}{2(x^2 + 16)}) + C

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