Substitution and Simplification: Simplify the integral using a substitution.Let u=x2+16, then du=2xdx.Rewrite dx in terms of du: dx=2xdu.Substitute into the integral:∫(x2+16)2x2dx=∫u2x2⋅(2xdu)=21⋅∫u2du
Further Simplification and Substitution: Simplify the integral further.The integral becomes:(21)⋅∫(u2du)=(21)⋅(−u1)+C=−(2u1)+CSubstitute back for u:=−(2(x2+16)1)+C
More problems from Evaluate definite integrals using the chain rule