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∫
x
2
−
4
2
x
d
x
\int \frac{x^{2}-4}{2 \sqrt{x}} d x
∫
2
x
x
2
−
4
d
x
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Math Problems
Calculus
Find indefinite integrals using the substitution and by parts
Full solution
Q.
∫
x
2
−
4
2
x
d
x
\int \frac{x^{2}-4}{2 \sqrt{x}} d x
∫
2
x
x
2
−
4
d
x
Separate Terms:
Simplify the integral by separating the terms in the numerator.
\newline
∫
x
2
−
4
2
x
d
x
=
1
2
∫
x
2
x
d
x
−
1
2
∫
4
x
d
x
\int \frac{x^2 - 4}{2\sqrt{x}} \, dx = \frac{1}{2} \int \frac{x^2}{\sqrt{x}} \, dx - \frac{1}{2} \int \frac{4}{\sqrt{x}} \, dx
∫
2
x
x
2
−
4
d
x
=
2
1
∫
x
x
2
d
x
−
2
1
∫
x
4
d
x
Simplify Integral:
Simplify each term in the integral.
\newline
1
2
∫
x
2
x
d
x
=
1
2
∫
x
3
/
2
d
x
\frac{1}{2} \int \frac{x^2}{\sqrt{x}} \, dx = \frac{1}{2} \int x^{3/2} \, dx
2
1
∫
x
x
2
d
x
=
2
1
∫
x
3/2
d
x
\newline
1
2
∫
4
x
d
x
=
2
∫
x
−
1
/
2
d
x
\frac{1}{2} \int \frac{4}{\sqrt{x}} \, dx = 2 \int x^{-1/2} \, dx
2
1
∫
x
4
d
x
=
2
∫
x
−
1/2
d
x
Integrate Terms:
Integrate each term.
\newline
1
2
∫
x
3
/
2
d
x
=
1
2
⋅
2
5
x
5
/
2
=
1
5
x
5
/
2
\frac{1}{2} \int x^{3/2} \, dx = \frac{1}{2} \cdot \frac{2}{5} x^{5/2} = \frac{1}{5} x^{5/2}
2
1
∫
x
3/2
d
x
=
2
1
⋅
5
2
x
5/2
=
5
1
x
5/2
\newline
2
∫
x
−
1
/
2
d
x
=
2
⋅
2
x
1
/
2
=
4
x
1
/
2
2 \int x^{-1/2} \, dx = 2 \cdot 2x^{1/2} = 4x^{1/2}
2
∫
x
−
1/2
d
x
=
2
⋅
2
x
1/2
=
4
x
1/2
Combine Integrated Terms:
Combine the integrated terms.
\newline
1
5
x
5
/
2
−
4
x
1
/
2
\frac{1}{5} x^{5/2} - 4x^{1/2}
5
1
x
5/2
−
4
x
1/2
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