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int_(0)^(4)(x)/(sqrt(1+2x))dx

04x1+2xdx \int_{0}^{4} \frac{x}{\sqrt{1+2 x}} d x

Full solution

Q. 04x1+2xdx \int_{0}^{4} \frac{x}{\sqrt{1+2 x}} d x
  1. Substitution: Let's do a substitution. Let u=1+2xu = 1 + 2x, then du=2dxdu = 2dx, or dx=du2dx = \frac{du}{2}.
  2. Change Limits: Change the limits of integration. When x=0x = 0, u=1+2(0)=1u = 1 + 2(0) = 1. When x=4x = 4, u=1+2(4)=9u = 1 + 2(4) = 9.
  3. Integral Transformation: Now substitute and change the integral: 04x1+2xdx=1219u1udu\int_{0}^{4}\frac{x}{\sqrt{1+2x}}dx = \frac{1}{2} \int_{1}^{9}\frac{u-1}{\sqrt{u}}du.
  4. Split Integral: Split the integral: 1219u1udu=12(19u12du19u12du).\frac{1}{2} \int_{1}^{9}\frac{u-1}{\sqrt{u}}du = \frac{1}{2} \left(\int_{1}^{9}u^{\frac{1}{2}}du - \int_{1}^{9}u^{-\frac{1}{2}}du\right).
  5. Find Antiderivatives: Find the antiderivatives: 12×(23u322u12)\frac{1}{2} \times \left(\frac{2}{3} u^{\frac{3}{2}} - 2 u^{\frac{1}{2}}\right) from 11 to 99.
  6. Plug in Limits: Plug in the limits of integration: \frac{\(1\)}{\(2\)} \times \left[\left(\frac{\(2\)}{\(3\)} \times \(9\)^{\frac{\(3\)}{\(2\)}} - \(2\) \times \(9\)^{\frac{\(1\)}{\(2\)}}\right) - \left(\frac{\(2\)}{\(3\)} \times \(1\)^{\frac{\(3\)}{\(2\)}} - \(2\) \times \(1\)^{\frac{\(1\)}{\(2\)}}\right)\right].
  7. Simplify Expression: Simplify the expression: \frac{11}{22} \times \left[\left(\frac{22}{33} \times 2727 - 22 \times 33\right) - \left(\frac{22}{33} \times 11 - 22 \times 11\right)\right].
  8. Calculate Result: Do the math: $\frac{\(1\)}{\(2\)} \times \left[(\(18\) - \(6\)) - \left(\frac{\(2\)}{\(3\)} - \(2\)\right)\right] = \frac{\(1\)}{\(2\)} \times [\(12\) - \left(-\frac{\(4\)}{\(3\)}\right)] = \frac{\(1\)}{\(2\)} \times \left(\(12\) + \frac{\(4\)}{\(3\)}\right).
  9. Convert to Common Denominator: Convert to a common denominator and add: \(\frac{1}{2} \times \left(\frac{36}{3} + \frac{4}{3}\right) = \frac{1}{2} \times \frac{40}{3}.\)
  10. Final Calculation: Multiply by \(\frac{1}{2}\): \(\left(\frac{1}{2}\right) \times \left(\frac{40}{3}\right) = \frac{20}{3}\).

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