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ind the value of Delta z for the system x-y+z=1,-3x+2y-3z=-6, x-5y+4z=5. -12 -6 12

ind the value of Δz \Delta z for the system x−y+z=1,−3x+2y−3z=−6 x-y+z=1,-3 x+2 y-3 z=-6 , x−5y+4z=5 x-5 y+4 z=5 .\newline−12 -12 \newline−6 -6 \newline1212

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Q. ind the value of Δz \Delta z for the system x−y+z=1,−3x+2y−3z=−6 x-y+z=1,-3 x+2 y-3 z=-6 , x−5y+4z=5 x-5 y+4 z=5 .\newline−12 -12 \newline−6 -6 \newline1212
  1. Use Elimination Method: We can use the method of elimination or substitution to solve for Δz\Delta z, but let's try elimination. We'll start by eliminating xx from equations 22 and 33 using equation 11.
  2. Eliminate x from Equations: Multiply equation 11 by 33 and add it to equation 22 to eliminate x:\newline3(x−y+z)=3(1)3(x - y + z) = 3(1)\newline−3x+2y−3z=−6-3x + 2y - 3z = -6\newlineThis gives us:\newline3x−3y+3z−3x+2y−3z=3−63x - 3y + 3z - 3x + 2y - 3z = 3 - 6\newline−y+2y=−3- y + 2y = -3\newliney=−3y = -3

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