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Let’s check out your problem:
in the space prov
\newline
b
\newline
3
8
−
18
3
8
−
3
3
\begin{array}{l} 3 \sqrt{8}-\sqrt{18} \\ 3 \sqrt{8}-3 \sqrt{3} \end{array}
3
8
−
18
3
8
−
3
3
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Home
Math Problems
Grade 8
Checkpoint: Rational and irrational numbers
Full solution
Q.
in the space prov
\newline
b
\newline
3
8
−
18
3
8
−
3
3
\begin{array}{l} 3 \sqrt{8}-\sqrt{18} \\ 3 \sqrt{8}-3 \sqrt{3} \end{array}
3
8
−
18
3
8
−
3
3
Simplify
8
\sqrt{8}
8
:
First, let's simplify
8
\sqrt{8}
8
and
18
\sqrt{18}
18
individually.
\newline
8
=
(
4
⋅
2
)
=
4
⋅
2
=
2
2
\sqrt{8} = \sqrt{(4\cdot2)} = \sqrt{4} \cdot \sqrt{2} = 2\sqrt{2}
8
=
(
4
⋅
2
)
=
4
⋅
2
=
2
2
.
Simplify
18
\sqrt{18}
18
:
Now, simplify
18
\sqrt{18}
18
.
18
=
(
9
⋅
2
)
=
9
⋅
2
=
3
2
\sqrt{18} = \sqrt{(9\cdot2)} = \sqrt{9} \cdot \sqrt{2} = 3\sqrt{2}
18
=
(
9
⋅
2
)
=
9
⋅
2
=
3
2
.
Substitute and Simplify:
Substitute the simplified forms back into the original expression.
3
8
−
18
3\sqrt{8} - \sqrt{18}
3
8
−
18
becomes
3
∗
(
2
2
)
−
3
2
.
3*(2\sqrt{2}) - 3\sqrt{2}.
3
∗
(
2
2
)
−
3
2
.
Multiply and Simplify:
Multiply
3
3
3
by
2
2
2\sqrt{2}
2
2
to simplify further.
\newline
3
×
(
2
2
)
=
6
2
3\times(2\sqrt{2}) = 6\sqrt{2}
3
×
(
2
2
)
=
6
2
.
Combine Like Terms:
Now we have
6
2
−
3
2
6\sqrt{2} - 3\sqrt{2}
6
2
−
3
2
. Since they are like terms, we can subtract the coefficients.
6
2
−
3
2
=
(
6
−
3
)
2
6\sqrt{2} - 3\sqrt{2} = (6-3)\sqrt{2}
6
2
−
3
2
=
(
6
−
3
)
2
.
Perform Subtraction:
Perform the subtraction.
\newline
(
6
−
3
)
2
=
3
2
(6-3)\sqrt{2} = 3\sqrt{2}
(
6
−
3
)
2
=
3
2
.
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