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In the given diagram, 
/_\ABE~=/_\CBD. Prove: 
/_\AFD~=/_\CFE

3333. In the given diagram, ABECBD \triangle A B E \cong \triangle C B D . Prove: AFDCFE \triangle A F D \cong \triangle C F E

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Q. 3333. In the given diagram, ABECBD \triangle A B E \cong \triangle C B D . Prove: AFDCFE \triangle A F D \cong \triangle C F E
  1. Identify Given Information: Identify given information and the goal.\newlineGiven: Triangles ABEABE and CBDCBD are similar, which means their corresponding angles are equal.\newlineGoal: To prove that triangles AFDAFD and CFECFE are similar.
  2. Use Similar Triangles: Use the fact that similar triangles have equal corresponding angles.\newlineSince triangles ABEABE and CBDCBD are similar, we have:\newlineABE=CBD\angle ABE = \angle CBD (by the definition of similar triangles).
  3. Identify Equal Angles: Identify other equal angles due to the geometry of the diagram.\newlineIn triangle AFDAFD and triangle CFECFE, we have:\newlineAFD\angle AFD and CFE\angle CFE are vertical angles, so they are equal.
  4. Use Transitive Property: Use the transitive property of equality to relate angles in different triangles.\newlineSince ABE=CBD\angle ABE = \angle CBD and ABE\angle ABE is also equal to AFD\angle AFD (as they are the same angle), we can say that AFD=CBD\angle AFD = \angle CBD.
  5. Identify Third Pair of Angles: Identify the third pair of equal angles using the fact that the sum of angles in a triangle is 180180 degrees.\newlineIn triangle AFD, the sum of angles is AFD+ADF+FDA=180\angle AFD + \angle ADF + \angle FDA = 180 degrees.\newlineIn triangle CFE, the sum of angles is CFE+CEF+FEC=180\angle CFE + \angle CEF + \angle FEC = 180 degrees.\newlineSince we have AFD=CFE\angle AFD = \angle CFE and ADF=CEF\angle ADF = \angle CEF (as they are corresponding angles in similar triangles ABE and CBD), it follows that FDA=FEC\angle FDA = \angle FEC.
  6. Conclude Similar Triangles: Conclude that triangles AFDAFD and CFECFE are similar. Since we have shown that all corresponding angles are equal (AFD=CFE\angle AFD = \angle CFE, ADF=CEF\angle ADF = \angle CEF, and FDA=FEC\angle FDA = \angle FEC), by the Angle-Angle (AA) similarity postulate, triangles AFDAFD and CFECFE are similar.

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