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$in the figure below, m/_2=63^(@). Find m/_1,m/_3, and m/_4. {:[m/_1=],[m/_3=],[m/_4=]:} ◻^(@) ◻$

in the figure below, $m \angle 2=63^{\circ}$ . Find $m \angle 1, m \angle 3$ , and $m \angle 4$ . $\newline$ $\begin{array}{l} m \angle 1= \\ m \angle 3= \\ m \angle 4= \end{array}$ $\newline$ $\square^{\circ}$ $\newline$ $\square$

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Negative exponents

Full solution

Q. in the figure below,

m \angle 2=63^{\circ}

. Find

m \angle 1, m \angle 3

, and

m \angle 4

.

\newline

\begin{array}{l} m \angle 1= \\ m \angle 3= \\ m \angle 4= \end{array}

\newline

\square^{\circ}

\newline

\square

Square Angles: Since $m/_{2}$ is $63$ degrees and it's a square, $m/_{4}$ is also $63$ degrees because opposite angles in a square are equal. $\newline$ $m/_{4} = 63$ degrees
Opposite Angles: A square has all angles equal to $90$ degrees, so $m/_{1}$ and $m/_{3}$ are each $90$ degrees. $\newline$ $m/_{1} = 90$ degrees $\newline$ $m/_{3} = 90$ degrees

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