Q. In the expansion of (1−3b)n in ascending powers of b, the coefficient of the third term is 324. Find the value of n using the binomial theorem.
Identify Binomial Expansion Form: Identify the general form of the binomial expansion.The binomial theorem states that (a+b)n=Σk=0n(kn)⋅a(n−k)⋅bk, where k goes from 0 to n.
Determine Third Term: Determine the third term in the expansion.The third term corresponds to k=2, so it is (2n) * 1n−2 * (−3b)2.
Simplify Third Term: Simplify the third term.The third term simplifies to (2n)×1×9b2, since 1(n−2) is always 1 and (−3b)2 is 9b2.
Set Coefficient Equal to 324: Set the coefficient of the third term equal to 324.(2n)×9=324.
Solve for (nchoose2): Solve for (nchoose2).(nchoose2)=9324.(nchoose2)=36.
Express in Factorial Form: Express (2n) in factorial form and solve for n.(2n)=2!(n−2)!n!.36=2!(n−2)!n!.
Substitute and Simplify: Substitute the value of 2! and simplify.36=2×(n−2)!n!.72=(n−2)!n!.
Find n: Find n by trial and error or algebraic manipulation.Assuming n is an integer, we can try different values of n to see which one satisfies the equation.For n=8, (8−2)!8!=(6×5×4×3×2×1)8×7×6×5×4×3×2×1=8×7=56, which is not correct.For n=9, (9−2)!9!=(7×6×5×4×3×2×1)9×8×7×6×5×4×3×2×1=9×8=72, which is correct.
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