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In the expansion of (13b)n(1-3b)^n in ascending powers of bb, the coefficient of the third term is 324324. Find the value of nn using the binomial theorem.

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Q. In the expansion of (13b)n(1-3b)^n in ascending powers of bb, the coefficient of the third term is 324324. Find the value of nn using the binomial theorem.
  1. Identify Binomial Expansion Form: Identify the general form of the binomial expansion.\newlineThe binomial theorem states that (a+b)n=Σk=0n(nk)a(nk)bk(a + b)^n = \Sigma_{k=0}^{n} \binom{n}{k} \cdot a^{(n-k)} \cdot b^k, where kk goes from 00 to nn.
  2. Determine Third Term: Determine the third term in the expansion.\newlineThe third term corresponds to k=2k = 2, so it is (n2)\binom{n}{2} * 1n21^{n-2} * (3b)2(-3b)^2.
  3. Simplify Third Term: Simplify the third term.\newlineThe third term simplifies to (n2)×1×9b2\binom{n}{2} \times 1 \times 9b^2, since 1(n2)1^{(n-2)} is always 11 and (3b)2(-3b)^2 is 9b29b^2.
  4. Set Coefficient Equal to 324324: Set the coefficient of the third term equal to 324324.(n2)×9=324\binom{n}{2} \times 9 = 324.
  5. Solve for (nchoose2)(n choose 2): Solve for (nchoose2)(n choose 2).(nchoose2)=3249(n choose 2) = \frac{324}{9}.(nchoose2)=36(n choose 2) = 36.
  6. Express in Factorial Form: Express (n2)\binom{n}{2} in factorial form and solve for nn.(n2)=n!2!(n2)!\binom{n}{2} = \frac{n!}{2!(n-2)!}.36=n!2!(n2)!36 = \frac{n!}{2!(n-2)!}.
  7. Substitute and Simplify: Substitute the value of 2!2! and simplify.\newline36=n!2×(n2)!36 = \frac{n!}{2 \times (n-2)!}.\newline72=n!(n2)!.72 = \frac{n!}{(n-2)!}.
  8. Find nn: Find nn by trial and error or algebraic manipulation.\newlineAssuming nn is an integer, we can try different values of nn to see which one satisfies the equation.\newlineFor n=8n = 8, 8!(82)!=8×7×6×5×4×3×2×1(6×5×4×3×2×1)=8×7=56\frac{8!}{(8-2)!} = \frac{8\times7\times6\times5\times4\times3\times2\times1}{(6\times5\times4\times3\times2\times1)} = 8\times7 = 56, which is not correct.\newlineFor n=9n = 9, 9!(92)!=9×8×7×6×5×4×3×2×1(7×6×5×4×3×2×1)=9×8=72\frac{9!}{(9-2)!} = \frac{9\times8\times7\times6\times5\times4\times3\times2\times1}{(7\times6\times5\times4\times3\times2\times1)} = 9\times8 = 72, which is correct.

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