13.In the diagram, P is the point of intersection of the curves y=e2x and y=e2−x.(i) Find the x-coordinate of P.Hence evaluate, correct to two decimal places,(ii) the area of the shaded region,(iii) the area of the region bounded by the two curves and the y-axis.
Q. 13.In the diagram, P is the point of intersection of the curves y=e2x and y=e2−x.(i) Find the x-coordinate of P.Hence evaluate, correct to two decimal places,(ii) the area of the shaded region,(iii) the area of the region bounded by the two curves and the y-axis.
Set Equations Equal: To find the x-coordinate of P, set the two equations equal to each other because at point P, the y-values of both curves are the same.e2x=e2−x
Take Natural Logarithm: Solve for x by taking the natural logarithm (ln) of both sides.ln(e2x)=ln(e2−x)
Use Logarithm Property: Use the property of logarithms that ln(ea)=a. 2x=2−x
Isolate Terms with x: Add x to both sides to isolate terms with x on one side.2x+x=2
Combine Like Terms: Combine like terms. 3x=2
Divide by 3: Divide both sides by 3 to solve for x.x=32
Find Area of Shaded Region: Now, to find the area of the shaded region, we need to integrate the difference between the two functions from the x-coordinate of P to the point where the curves meet the y-axis.However, we have not yet found the x-coordinate where the curves meet the y-axis. This is a mistake because we need these x-coordinates to set the limits of integration.
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